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A square coil of 10^(-2) m^(2) area is p...

A square coil of `10^(-2) m^(2)` area is placed perpenducular to a uniform magnetic field of `10^(3) Wb//m^(2)`. What is magnetic flux through the coil?

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To find the magnetic flux through a square coil placed perpendicular to a uniform magnetic field, we can use the formula for magnetic flux (Φ): \[ \Phi = B \cdot A \cdot \cos(\theta) \] where: - \( \Phi \) is the magnetic flux, ...
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