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The current passing through a choke coil...

The current passing through a choke coil of `5` hery is decreasing at the rate of `2 ampere//sec`. The e.mf. Devlopeing across the coil is

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Here, `L = 5 H, (d I)/(dt) = 2 A//s, e = ?`
`e = L (d I)/(dt) = 5 xx 2 = 10 V`
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