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The self inductance of a coil having 200...

The self inductance of a coil having 200 turns is 10 mH. Complete the total flux linked with the coil. Also, determine the magnetic flux through the cross section of the coil, corresponding to current of 4 mA.

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To solve the problem, we will follow these steps: ### Step 1: Understand the given data - Number of turns (N) = 200 - Self-inductance (L) = 10 mH = 10 × 10^(-3) H - Current (I) = 4 mA = 4 × 10^(-3) A ### Step 2: Calculate the total magnetic flux linked with the coil ...
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