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Magnetic field of 2 xx 10^(-2) Wb m^(2) ...

Magnetic field of `2 xx 10^(-2)` Wb `m^(2)` is acting at right angle to a coil of 1000 `cm^(2)` having 50 turns. The coil is removed from the field in `(1)/(10)` second. Find the magnitude of induced e.m.f.

Text Solution

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Here, `B_(1) = 2 xx 10^(-2) Wb m^(2), theta = 0^(@)`
`A = 1000 cm^(2) = 1000 xx 10^(-4) m^(2) = 10^(-1) m^(2)`,
`N = 50`,
`B_(2) = 0, dt = (1)/(10) s, e = ?`
`e = (-d phi)/(dt) = - (N (B_(2) - B_(1)) A)/(dt)`
`= - (50 (0 - 2 xx 10^(-2)) 10^(-1))/(1//10) = 1.0 V`
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