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The average e.m.f. induced in a coil in ...

The average e.m.f. induced in a coil in which the current changes from `2` amperes to `4` amperes in `0.05` seconds is `8` volts. What is the self-inductance of the coil?

Text Solution

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Here, `e = 8 V, dI = 4 - 2 = 2 A`,
`dt = 0.05 s, L = ?`
Form `e = L (dI)/(dt)`
`L = e . (dt)/(dI) = (8 xx 0.05)/(2) = 0.2 H`
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