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A cell of 1.5V is connected across an in...

A cell of `1.5V` is connected across an inductor of `2mH` in series with a `2 Omega` resistor. What is the rate of growth of current immediately after the cell is switched on.

Text Solution

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Here, `E = 1.5 V, L = 2 mH = 2 xx 10^(-3) H, R = 2 Omega`
At any time, `E = RI + L dI // dt`
When the cell is switched on, current starts growing from zero value, `I = 0`,
`:. E = (L dI)/(dt)` or `(dI)/(dt) = (E)/(L) = (1.5)/(2 xx 10^(-3)) = 750 A s^(-1)`
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