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220 V, Hz is connected across a capacito...

220 V, Hz is connected across a capacitor of `5 mu F`. Calculate the effective current.

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Here, `E_(V) = 220 V, v = 50 Hz, C = 5 xx 10^(-6) F`
`X_(C) = (1)/(omega C) = (1)/( 2 pi v C) = (1)/(2 pi xx 50 xx 5 xx 10^(-6)) = (10^(6))/(500 pi) ohm`
`I_(v) = (E_(v))/(X_(C)) = (220 xx 500 pi)/(10^(6)) = 0.11 xx 3.14 A = 0.375 A`
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