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In an a.c. circuit, the rms voltage is 1...

In an a.c. circuit, the rms voltage is `100 sqrt 2 V`. Find the peak value of voltage and its means value during a positve half cycle.

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To solve the problem step by step, we will find the peak value of the voltage and then calculate the mean value during a positive half cycle. ### Step 1: Find the Peak Value of Voltage The relationship between the RMS (Root Mean Square) voltage \( V_{rms} \) and the peak voltage \( V_0 \) is given by the formula: \[ V_0 = \sqrt{2} \times V_{rms} \] Given that the RMS voltage is \( V_{rms} = 100\sqrt{2} \, V \), we can substitute this value into the formula. ...
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Knowledge Check

  • In an A.C. circuit the peak value of voltage is 424V. Its effective voltage is

    A
    a. 340V
    B
    b. 320V
    C
    c. 250V
    D
    d. 300V
  • In an AC circuit the maximum value of voltage is 423 volt, Its effective voltage is :-

    A
    400 volt
    B
    300 volt
    C
    323 volt
    D
    340 volt
  • The peak value of alternating voltage is 423 V. its root mean square value is

    A
    300 V
    B
    423 V
    C
    `423sqrt(2)V`
    D
    zero
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