Home
Class 12
PHYSICS
A series LCR circuit is connected to an ...

A series LCR circuit is connected to an a.c. source 200 V, 50 Hz. The voltages acorss the resistor, indcutor and capacitor are respectively 200 V, 250 V and 250 V. (i) The algerbriac sum of the three voltages is greater than the source voltage. How is the paradox resolved ?
(ii) If `R = 40 Omega`, calculate the current in the circuit.

Text Solution

AI Generated Solution

### Step-by-Step Solution: **Given:** - Source Voltage, \( V = 200 \, V \) - Frequency, \( f = 50 \, Hz \) - Voltage across Resistor, \( V_R = 200 \, V \) - Voltage across Inductor, \( V_L = 250 \, V \) - Voltage across Capacitor, \( V_C = 250 \, V \) ...
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    PRADEEP|Exercise Solved Examples (b)|1 Videos
  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    PRADEEP|Exercise Short Answer Qusetions|2 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    PRADEEP|Exercise Exercise|191 Videos
  • ELECTROMAGNETIC WAVES

    PRADEEP|Exercise II Focus multiple choice question|5 Videos

Similar Questions

Explore conceptually related problems

In a series RC circuit connected across an AC source of 220 V 50 Hz calculate the rms voltage across resistor and capacitor if values of R and C are 100 Omega and 20 μF respectively .

A series LCR circuit is connected top an AC power source of 220 V , 50 Hz. The values of L and R are 0.41 H and 80 Omega respectively. What is the value of C if current and voltage are in phase ?

An LCR series circuit is connected to an oscillator (AC supply) having RMS voltage 200 V. If the RMS voltages across resistor, inductor and capacitor are equal, then RMS voltage across the resistor would be

In a series LCR circuit the rms voltage across the inductance , capacitance and resistance are respectively 4 V, 8 V and 5 V . The RMS voltage of the AC source in the circuit is

A series LCR circuit is connected to an a.c. source of 220 V - 50 hz. If the readings of voltmeters acorss resistor, capacitor and inductor are 65 V, 415 V and 204 volt respectively , and R = 100 Omega calculate (i) current in the circuit (ii) value of L (iii) valueo of C and (iv) capacitance required to produce resonance with the given inductor L.

In a series RC circuit, R = 30 ohm, C = 0.25 mu F , V = 100 V, omega = 10000 rad//s . Find the current in the circuit and calculate the voltage across the resistor and capacitor. Is the algebraic sum of these voltages more than the source voltage ? If yes, resolve the paradox.

A resistance of 200Omega and capacitor of 15muF are connected in series to a 220 V, 50 Hz AC source. The voltage (rms) across the resistor and capacitor is that

In a series L-C circuit, the applied voltage is V_0. if omega is very low, then the voltage drop across the inductor V_L and capacitor V_C are .

In a series LCR circuit the voltage across an inductor, capacitor and resistor are 20 V, 20 V and 40 V respectively. The phase difference between the applied voltage and the current in the circuit is