Show that the sum of instantaneous currents during growth and decay of current in LR circuit is independent of time.

Explanation

During growth of current in LR circuit,
`I_(g) = I_(0) (1 - e^(-Rt//L))` and
during decay of current in LR circuit,
`I_(d) = I_(0) e^(-Rt//L)`
Sum of the currents at any instant t,
`I_(g) + I_(d) = I_(0) (1 - e^(-Rt//L) + e^(-Rt//L)) = I_(0)`
which is constant, and is independent to time.