Home
Class 12
PHYSICS
A bulb B a capacitor C are connected in ...

A bulb B a capacitor C are connected in series to an a.c. source. A dielectric slab is now introduced between the plates of the capacitor. How will the brightness of bulb change ?

Text Solution

AI Generated Solution

To solve the problem of how the brightness of the bulb changes when a dielectric slab is introduced between the plates of a capacitor connected in series with an AC source, we can follow these steps: ### Step 1: Understand the Circuit Configuration We have a bulb (B) and a capacitor (C) connected in series to an AC source. The brightness of the bulb depends on the current flowing through the circuit. **Hint:** Remember that the brightness of a bulb is directly proportional to the current flowing through it. ### Step 2: Analyze the Effect of the Dielectric ...
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    PRADEEP|Exercise Solved Examples (b)|1 Videos
  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    PRADEEP|Exercise Short Answer Qusetions|2 Videos
  • DUAL NATURE OF RADIATION AND MATTER

    PRADEEP|Exercise Exercise|191 Videos
  • ELECTROMAGNETIC WAVES

    PRADEEP|Exercise II Focus multiple choice question|5 Videos

Similar Questions

Explore conceptually related problems

A dielectric slab is placed between the plates of a parallel plate capacitor. Its capacitance

Two identical capacitors are connected as shown in fignre. A dielectric slab is introduced between the plates of one of the capacitors so as to fill the gap, the battery remaining connected. What will be the capacitance, the charge, potential difference and stored energy for each capacitor?

Two identical capacitors are connected as shown. A dielectric slab Is introduced between the plates of one of the capacitors so as to fill the gap, the battery remaining connected. Compare the capacitance, the charge, potential difference and stored energy of each capacitor before and arter introducting of dielectric slab.

Two identical parallel plate capacitors are connected in series to a battery of 100V . A dielectric slab of dielectric constant 4.0 is inserted between the plates of second capacitor. The potential difference across the capacitors will now be respectively

While a capacitor remains connected to a battery and dielectric slab is applied between the plates, then

Explain why the capacitance of a parallel plate capacitor increases when a dielectric slab is introduced between the plates.

There is an air capacitor with capacitance C, charged to a potential difference of V. If the capacitor is isolated from the battery after charging, and then a dielectric slab is inserted in between the plates of capacitor. How will the energy stored in this capacitor change?

A capacitor of capacitance C is connected to a battery of V volts. A dielectric k=(7)/(3) is introduced betwene the plates of the capacitor when battery is connected.The ratio of energies stored in the capacitor without dielectric and with dielectric..