Home
Class 12
PHYSICS
Explain : voltages across L and C in ser...

Explain : voltages across L and C in series are `180^(@)` out of phase, while for L and C in parallel, current in L and C are `180^(@)` out of phase.

Text Solution

Verified by Experts

When L and C in series, for a given a.c., voltage acorss L leads `pi//2`.and voltage across C lags by `pi//2`. Therefore, voltages acorss L and C differ in phase by `pi`
When L and C are in parallel, for a given voltage, current in L lag by `pi//2` and current in C leads by `pi//2`. Therefor, currents in L and C differ in phase by `pi`.
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    PRADEEP|Exercise Solved Examples (b)|1 Videos

  • ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT

    PRADEEP|Exercise Short Answer Qusetions|2 Videos

  • DUAL NATURE OF RADIATION AND MATTER

    PRADEEP|Exercise Exercise|191 Videos

  • ELECTROMAGNETIC WAVES

    PRADEEP|Exercise II Focus multiple choice question|5 Videos

Similar Questions

Explore conceptually related problems

Phase difference between voltages across L and C in series is

When L and C are in series, voltage across them is in phase (True/false). The current in them is in phase (true/false).

For a series R-L-C circuit :- (a) Voltage across L and C are differ by pi (b) Current through L and R are in same phase (c) Voltage across R and L differ by pi//2 (d) Voltage across L and current through C are differ by pi//2

In series LCR circuit, the voltages across R, L and C are shown in the figure. The voltage of applied source

In an LCR series circuit the voltages across R,L and C at resonance are 40 V and 60V respectively the applied voltage is .

The current in the series L-C-R circuit is

In series LCR circuit, the phase difference between voltage across L and voltage across C is

In a series C-R circuit shown in figureure, the applied voltage is 10 V and the voltage across capacitor is found to 8 V . The voltage across R , and the phase difference between current and the applied voltage will respectively be .