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What is the average value of atlernating...

What is the average value of atlernating current, `I = I_(0) sin omega t` over time interval `t = pi//omega` to `t = pi//omega` ?

Text Solution

AI Generated Solution

To find the average value of the alternating current given by the equation \( I = I_0 \sin(\omega t) \) over the time interval \( t = \frac{\pi}{\omega} \) to \( t = \frac{2\pi}{\omega} \), we can follow these steps: ### Step 1: Identify the Time Interval The time interval given is from \( t = \frac{\pi}{\omega} \) to \( t = \frac{2\pi}{\omega} \). This corresponds to half of the complete cycle of the sine wave, as the full cycle (period \( T \)) is \( T = \frac{2\pi}{\omega} \). ### Step 2: Set Up the Average Value Formula The average value \( I_{\text{avg}} \) of a function over a time interval \( [t_1, t_2] \) is given by the formula: \[ ...
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Knowledge Check

  • The average value of alternating current I=I_(0) sin omegat in time interval [0, pi/omega] is

    A
    `(2I_(0))/pi`
    B
    `2I_(0)`
    C
    `(4I_(0))/pi`
    D
    `I_(0)/pi`
  • The average value of a.c. voltge E =E_(0) sin omega t over the time interval t = 0 to t = pi//omega is

    A
    `- 2 E_(0)//pi`
    B
    `E_(0)//pi`
    C
    `(2 E_(0))/(pi)`
    D
    zero
  • The average value of an alternating voltage V=V_(0) sin omega t over a full cycle is

    A
    `V_(0)`
    B
    `(V_(0))/(Sqrt(2))`
    C
    `(2V_(0))/(pi)`
    D
    Zero
  • Similar Questions

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    Find the rms value of current i=I_(m)sin omegat from (i) t=0 "to" t=(pi)/(omega) (ii) t=(pi)/(2omega) "to" t=(3pi)/(2omega)

    R.M.S vaue of current I = 3 + 4 sin (omega t + pi//3) is :

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