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An iron rod is inserted in the inductor,...

An iron rod is inserted in the inductor, what will be the effect on the brightness of the bulb?

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Current through the bulb
`I_(v) = (E_(v))/(Z) = (E_(v))/(sqrt(R^(2) + X_(L)^(2)))`, where `X_(L) = omega L`
On introducing an iron rod into the inductro its inductance L increases. `X_(L) = omega L` increases. Therefore, impedance Z increases. Current `I_(v)` through the bulb decreases. Hence brightness of bulb decreases.
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