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A 66 % efficient transformer is working ...

A 66 % efficient transformer is working on 110 V and 2.2 kW power.If current in secondary coil is 6.0 A, calculate (i) current in primary coil and (ii) voltage across secondary coil.

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Here, `eta = 66//100, E_(p) = 110 V`,
`P_(p) = 2.2 kW = 2200 W`
`I_(s) = 6.0 A, I_(p) = ?, E_(s) = ?`
As `P_(p) = E_(p) I_(p) :. I_(p) = P_(p)//E_(p) = (2200)/(110) = 20 A`
As `eta = (E_(s) I_(s))/(E_(p) I_(p)) :. (66)/(100) = (E_(s) xx 6)/(2200)`
`E_(s) = (66 xx 2200)/(100 xx 6) = 242 V`
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