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A transformer has an efficiency of 80%. ...

A transformer has an efficiency of 80%. It delivers 2kW output power at 100 V primary and 240 V secondary voltages. Calculate primary and secondary currents

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Here, `eta = 80% P_(o) = 2 kW = 200 W`
`E_(p) = 100 V, E_(s) = 240 V, I_(p) = ? I_(s) = ?`
`eta = (P_(o))/(P_(i)) , P_(i) = (P_(o))/(eta) = (2000)/(80//100) = 2500 W`
As `P_(i) = E_(p) I_(p)`
`:. I_(p) = (P_(i))/(E_(p)) = (2500)/(100) = 25 A`
`I_(s) = (P_(o))/(E_(s)) = (2000)/(240) = 8.33 A`
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