You are given a fixed length of wire to design a generator. For a given magnetic field strength and given frequency of rotation, will you use one turn or two turn square coil to generate maximum peak e.m.f. ?

Explanation

As in known, the peak e.m.f. is given by
`e_(0) = NAB omega`.
As B and `omega`fixed, `e_(0)` will be maximum,
when `N xx A =` maximum. Let L be length of given wire.
If `N = 1, A = (L//4)^(2) = (L^(2))/(16) , NA = 1 xx (L^(2))/(16) = (L^(2))/(16)`
If `N = 2, A = (L//8)^(2) = (L^(2))/(64) , NA = 2 xx (L^(2))/(64) = (L^(2))/(32)`
Hence one turn square coil can be be used to generated maximum peak e.m.f.