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Suppose the loop in Q.4 is stationary, b...

Suppose the loop in Q.4 is stationary, but the current feeding the electromagnet the produces the magnetic field is gradually reduced so that the field decreases form its initial value of 0.3 T at the rate of 0.2 `T//sec`. If the cut is joined and loop has a resistance of `1.6 Omega`, how much power is dissipated by the loop as heat ? What is the source of this power ?

Text Solution

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Here, `A = 8 xx 2 = 16 cm^(2) = 16 xx 10^(-4) m^(2) (dB)/(dt) = 0.02 tesla//sec`.
`e = ?` `e = (d phi)/(dt) = (A dB)/(dt) = 16 xx 10^(-4) xx 0.02 = 0.32 xx 10^(-4) `volt
Now, `R = 1.6 Omega`
Induced current, `i = (e)/(R ) = (0.32 xx 10^(-4))/(1.6) = 0.2 xx 10^(-4)` amp.
Power dissipated as heat `= i^(2) R = (0.2 xx 10^(-4))^(2) xx 1.6 = 0.604 xx 10^(-8)` watt ` = 6.4 xx 10^(-10)` watt.
Source of this power is the external agency changing the magnetic field with time.
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