A `60 mu F` capacitor is connected to a 110 V, 60 Hz a.c. supply Determine the r.m.s value of current in the circuit.

Explanation

Here, `C = 60 mu F = 60 xx 10^(-6) F, E_(v) = 110 V, v = 60 hz, I_(v) = ?`
`I_(v) = (E_(v))/(X_(C )) = (E_(v))/(1//2 pi v C) = (2 pi v C) E_(v) = 2 xx 3.14 xx 60 xx (60 xx 10^(-6)) xx 110 = 2.49 A`