A 100 mH inductor and a `50 mu F` capacitor in series are connected to a 200 V, 50 Hz supply. Calcualte rms value of current and potential drops across each element. What is the average power transferred to the inductor and also to the capacitor and the total average power absorbed ?

Explanation

Here, `L = 100 mH = 100 xx 10^(-3) H = 10^(-1), c = 50 mu F = 50 xx 10^(-6) F = 5 xx 10^(-5) F, E_(v) = 200 V, v = 50 Hz`
Impedance of the circuit : `X_(L) = omega L = 2 pi L = 2 pi xx 50 xx 10^(-1) = 10 pi = 31.4 ohm`
`X_(C ) = (1)/(omega C) = (1)/(2 pi v C) = (1)/(2 pi xx 50 xx 5 xx 10^(-5)) = 63.7 Omega`
Potential drop across inductor, `V_(L) = I_(v) X_(L) = 6.19 xx 31.4 = 194.4 V`
Potential drop across condenser `V_(C ) = I_(v) X_(C ) = 6.19 xx 63.7 = 394.3 V`
Average power transferred to inductor `= E_(v) I_(v) cos 90^(@) = 0`
Average power transferred to capacitor `= E_(v) I_(v) cos 90^(@) = 0`
`:.` Total power absorbed = 0 + Zero