What is the self inductance of a coil, in which magnetic flux of 40 milliweber is produced when 2 A current flows through it?

Explanation

To find the self-inductance \( L \) of a coil, we can use the relationship between magnetic flux \( \Phi \), current \( I \), and self-inductance. The formula that relates these quantities is given by:

\[ \Phi = L \cdot I \]

Where:
- \( \Phi \) is the magnetic flux in webers,
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