A positive integer n is of the form n=2^...

A positive integer `n` is of the form `n=2^(alpha)3^(beta)`, where `alpha ge 1`, `beta ge 1`. If `n` has `12` positive divisors and `2n` has `15` positive divisors, then the number of positive divisors of `3n `is

Similar Questions

Explore conceptually related problems

If n is a positive integer such that 2n has 28 positive divisors and 3 n has 30 positive divisors,then findthe positive divisors of 6n

A natural number n has exactly two divisors and (n+1) has three divisors.The number of divisors of (n+2) is

For a positive integer n, define d(n) - the number of positive divisors of n. What is the value of d(d(d(12))) ?

If N=2^(n-1).(2^n-1) where 2^n-1 is a prime, then the sum of the all divisors of N is

If a number n is divisible by 8 and 30, then the smallest number of divisors that n has is

If n is a positive integer then 2^(4n) - 15n - 1 is divisible by

If the expansion of (x^(2)+(2)/(x))^(n) for positive integer n has 13th term independennt of x, then the sum of divisors of n is: