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The self inductance of an inductance coi...

The self inductance of an inductance coil having 100 turns is 20 mH. Calculate the magnetic flux through the cross section of the coil corresponding to a current of 4 milliampere. Also, find the total flux

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To solve the problem, we will follow these steps: ### Step 1: Understand the given data - Self-inductance (L) = 20 mH = 20 × 10⁻³ H - Number of turns (N) = 100 - Current (I) = 4 mA = 4 × 10⁻³ A ### Step 2: Calculate the magnetic flux (Φ) through the cross-section of the coil ...
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PRADEEP-ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT-Exercise
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