Compute the mutual inductance for a given pair of coils if increase in current from 2 A to 6 A in 0.1 s in one coil causes an induced e.m.f. of 1 V in the order coil.

Explanation

Here, `A = 8 xx 2 = 16 sq cm = 16 xx 10^(-4) m^(-2)`
`(dB)/(dt) = - 0.02 Ts^(-1)`
Induced e.m.f. `e = (- d phi)/(dt) = - (A dB)/(dt)`
` = - 16 xx 10^(-4) (- 0.02) = 32 xx 10^(-6) V`
Power loss `= (e^(2))/(R ) = ((32 xx 10^(-6))^(2))/(1.6)`
`= 6.4 xx 10^(-10) W`