A capacitor of `2 mu F` is conneted to 10 V supply through 1 mega ohm resistance. How long will it take the capacitor to charge upto 63.2% of its final charge ? Also, calculate the maximum value of charge.

Explanation

Here, `C = 2 mu F, = 2 xx 10^(-6) F, E = 10` volt
`R = 10^(6) ohm, t = ?, q = 63.2% q_(0)`
By definition, `q = 63.2% q_(0)` in `t = tau = RC`
`:. T = 10^(6) xx 2 xx 10^(-6) = 2 sec`.
`q_(0) = CE = 2 xx 10^(-6) xx 10 = 2 xx 10^(-5) C`