If the effective current in a 50 cycles a.c. cuicuit is 5 A, what is the peak value of current ? What is the current `1//600` sec. after it was zero ?

Explanation

Here, `I_(v) = 5 A, I_(0) = sqrt2 I_(v) = 1.414 xx 5 = 7.07 A`
From `I = I_(0) sin omega t`
`I = 7.07 sin 2 pi xx 50 xx (1)/(600)`
`= 7.07 (sin) (pi)/(6) = 7.07 xx (1)/(2) = 3.535 A`