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A resistance of 40 Omega is connected to...

A resistance of `40 Omega` is connected to an source of 220 v, 50 Hz. Find the (i) rms current (ii) maximum instantaneous current in resistor.

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Here, `R = 40 Omega, E_(v) = 200 V, v = 50 Hz`
`I_(v) = (E_(v))/(R ) = (220)/(40) = 5.5 A`
Max. instantaneous current, `I_(0) = sqrt2 I_(v)`
`= 1.414 xx 5.5 = 7.8 A`
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