A capacitor of capacitance `10 muF` is connected to an oscillator giving an output voltage `epsilon = (10 V) sin omegat`. Find the peak currents in the circuit for `omega = 10 s^(-1), 100 s^(-1), 500 s^(-1), 1000 s^(-1)`.

Explanation

Here, `C = 10 mu F = 10 xx 10^(-6) F, E = 10 sin omega t`,
`:. E_(0) = 10 V, omega = 10 rad//s, I_(0) = ?, I = ?`
`I_(0) = (E_(0))/(X_(C )) = (E_(0))/(1//omega C) = omega C E_(0)`
`= 10 xx 10^(-5) xx 10 = 10^(-3) A = 1.0 mA`
Through a capacitor, current leads the applied voltage by a phase angle of `90^(@)`
`:. I = I_(0) sin (omega t + pi//2) = 10^(-3) sin (omega t + pi//2)`