A `3 mu F` capacitor is connected to a 220 V, 50 Hz a.c. source. Calculate the rms value of current through the circuit. Also, find the peak value of voltage across the capacitor.

Explanation

Here, `C = 3 xx 10^(-6) F, E_(v) = 220 V, v = 50 hz`
`I_(v) = ?, E_(0) = ?`
`I_(v) = (E_(v))/(X_(C )) = (E_(v))/(1//omega C) = E_(v) (omega C) = E_(v) (2 pi v C)`
`I_(v) = 220 xx 2 xx (22)/(7) xx 50 xx 3 xx 10^(-6) = 0.207 A`
`E_(0) = sqrt2 E_(v) = 1.414 xx 220 = 311.1 V`