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A current of 30 mA is taken by a 4 mu F ...

A current of 30 mA is taken by a `4 mu F` capacitor connected acorss an alternating current line having frequency of 500 Hz. Calculate reactance of the capacitor and voltage across the capacitor.

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Here, `I_(v) = 30 mA = 30 xx 10^(-3) A`,
`C = 4 mu F = 4 xx 10^(-6) F`
`v = 500 Hz, X_(C ) = ? V _(C ) = ?`
`X_(C ) = (1)/(omega C) = (2)/(2 pi v xx C)`
`(1)/(2 xx 3.14 xx 500 xx 4 xx 10^(-6))`
`= (1000)/(12.56) = 79.6 Omega`
`V_(C ) = I_(v) X_(C ) = 30 xx 10^(-3) xx 79. 6 = 2.4 V`
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PRADEEP-ELECTROMAGNETIC INDUCTION & ALTERNATING CURRENT-Exercise
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