An inductor L, capacitor of `20 mu F` and a resistor of `10 Omega` are connected in series with 220 V, 50 Hz a.c. supply. If current is in phase with the voltage, calculate the inductance. What is the value of current in the circuit ?

Explanation

To solve the problem step by step, we will follow the principles of AC circuits, particularly focusing on the resonance condition where the current is in phase with the voltage.

### Step 1: Understanding the Condition
Since the current is in phase with the voltage, this indicates that the circuit is in resonance. In resonance, the inductive reactance (X_L) is equal to the capacitive reactance (X_C).

### Step 2: Define the Given Values
- Capacitor (C) = 20 µF = 20 × 10^(-6) F
- Resistor (R) = 10 Ω
...