A series LER circuit with `C = 80 mu F`, L = 5.0 H and `R = 40 Omega` is connected to a variable frequency 240 V a.c. source Calculate
(i) angular frequency of the source which drives the circuit in resonanace.
(ii) current at the resonating frequency.
(iii) rms pot. drop across the capacitor.

Explanation

Here, `C = 80 mu F = 80 xx 10^(-6) F, L = 5.0 H`,
`R = 40 Omega, E_(v) = 240 V`
(i) `omega = (1)/(sqrt(LC)) = (1)/(sqrt(5.0 xx 80 xx 10^(-6))) = (10^(3))/(20)`
`= 50 rad//s`
(ii) At resonating frequency, `Z = R = 40 Omega`
`I_(v) = (E_(v))/(Z) = (240)/(40) = 6A`
(iii) `V_(C ) = I_(v) . X_(C ) = 6 xx (1)/(omega C) = 6 xx (1)/(50 xx 80 xx 10^(-6))`
` = 1500 V`