Calculate the value of inductance, which should be connected in series with a capacitance of `5 mu F` and resistance of 10 ohm with a.c. source of 50 Hz, so that power factor of the circuit is unity.

Explanation

Here, `L = ? C = 5 mu F = 5 xx 10^(-6) F`
`R = 10 ohm`
`v = 50 Hz`
Power factor in uinty at resonance, where
`omega L = (1)/(omega C)`
or `L = (1)/(omega^(2) C) = (1)/(4 pi^(2) v^(2) C)`
`= (1)/(4 xx 3.14 xx (50)^(2) xx 5 xx 10^(-6))`
`L = 2.028 H`