A flat coil of 500 turns each of area `50 cm^(2)` rotates in a uniform magnetic field of `0.14 Wb//m^(2)` at an angular speed of `150 rad//sec`. The coil has a resistance of `5 Omega`. The induced e.m.f. is applied to an external resistance of 10 ohm. Calculate the peak current through the resistance.

Explanation

Here, `N = 500, A = 50 cm^(2) = 50 xx 10^(-4) m^(2)`
`B = 0.14 Wb//m^(2), omega = 150 rad//s`,
`R = 5 Omega R' = 10 Omega, i_(0) = ?`
`e_(0) = NAB omega = 500 xx 50 xx 10^(-4) xx 0.14 xx 150`
`= 52.5` volt
As total resistance `= R + R' = 5 + 10 = 15 Omega`
`:. i_(0) = (e_(0))/(15) = (52.5)/(15) = 3.5 A`