The output of a step-down transformer is measured to be `24 V` when connected to a 12 watt light bulb. The value of the peak current is

Options

A. `1 sqrt2 A`
B. `sqrt2 A`
C. `2 A`
D. `2 sqrt2 A`

Answer

A

Explanation

Here, `E_(s) = 24 V, P_(s) = 12 W, I_(0) = ?`
`I_(s) = (P_(s))/(E_(s)) = (12)/(24) = (1)/(2) A` `I_(0) = sqrt2 I_(s) = sqrt2 xx (1)/(2) = 1 // sqrt2 A`.