As shown in the figure, P and Q are two coaxial conducting loops separated by some distance. When the switch S is closed, a clockwise current `I_(P)` (as seen by E) and an induced current `I_(Q1)` flows in Q. The switch remains closed for a long time. when S is opened, a current `I_(Q2)` flows in Q. Then the direction `IQ_(1) and IQ_(2)` (as seen by E) are

Options

A. respectively clockwise and anticlockwise
B. both clockwise
C. both anticlockwise
D. respectively anticlockwise and clockwise

Answer

D

Explanation

When switch S is closed, Fig. current in coil P increases in clockwise direction. Induced currrent in Q must opposei this increase, as per Len'z law. Therefore, induced current in Q i.e., `I_(Q1)` must be anticlockwise.
When switch S is opened current in coil P decreases. Induced current in Q oppoes this decrease. as per Lenz's law. Therefore,induced current in Q, i.e., `I_(Q2)` must be clockwise.