A closed coil consists of 500 turns has area `4 cm^2` and a resistance of `50 Omega`. The coil is kept with its plane perpendicular to a uniform magnetic field of `0.2 Wb/m^2`. Calculate the amount of charge flowing through the coil if it is rotated through `180^@`

Options

A. `1.67 xx 10^(-2) C`
B. `1.67 xx 10^(-3) C`
C. `1.67 xx 10^(-4) C`
D. `1.76 xx 10^(-3) C`

Answer

D

Explanation

Here, `n = 500, A = 4 cm^(2) = 4 xxx 10(-4), Q = ?`
`R = 50 ohm, V = 0.22 Wb m^(-2), Q = ?`
As the coil is rotated through `180^(@)`, change in magnetic flux linked with the coil
`Detla phi = n BA = 2 xx 500 xx 0.22 xx 4 xx 10^(-4)`
`= 8.8 xx 10^(-2) Wb`
`Q = (Delta phi)/(R ) = (8.8 xx 10^(-2))/(50) = 1.76 xx 10^(-3) C`