A long solenoid has `1000` turns. When a current of `4A` flows through it, the magnetic flux linked with each turn of the solenoid is `4xx10^(-3)Wb`. The self-inductance of the solenoid is

Options

A. ` 3 H`
B. ` 2 H`
C. `1 H`
D. `4 H`

Answer

C

Explanation

Here, `N = 100m I = 4A, phi_(turn) = 4 xx 10^(-3) = 4 Wb`,
`L = ?`
Total flux, `phi = N phi_(turn) = 1000 xx 4 xx 10^(-3) = 4 Wb`
From `phi = LI, L = (phi)/(I) = (4)/(4) = 1 H`