In the series `RLC` circuit as shown in Fig., what would be the ammeter reading in ampere ?

Answer

2

Explanation

As `V_(L) = V_(C ) = 200 V`
`:.` The circuit is series resonance circuit `Z = R`
`I_(upsilon) = (E_(upsilon))/(Z) = (E_(upsilon))/(R ) = (100)/(50) 2 A`