An a.c. source of voltage `V = 100 sin 100 pi t`. Is connected to a resistor of `(25)/(sqrt2) ohm`. What is the r.m.s value of current (in ampere) through the resistor ?

Answer

4

Explanation

Here, `V = 100 sin pi t, R = (25)/(sqrt2) ohm`.
Compare with the stantard form `V = E_(0) sin omega t`
`E_(0) = 100`, Volt , `E_(upsilon) = (E_(0))/(sqrt2) = (100)/(sqrt2)` volt
`I_(upsilon) = (E_(upsilon))/(R ) = (100 // sqrt2)/(25 // sqrt2) = 4 A`