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Calculate the peak values of electric and magnetic fields produces by the radiation coming form a 100watt bulb at a distance of 3m. Assume that the efficiency of the bulb is 2.5% and it is a point source?

Text Solution

Verified by Experts

Useful Intensity,
`I=("power")/("area") =(100xx(2.5//10))/(4pi(3)^2)=2.5/(36pi)Wm^-2`
Half of this intensity (I) belongs to electric field
and half of that of magnetic field. Therefore,
`I/2=1/4in_0E_0^2c`
or `E_0=sqrt((2I)/(in_0c))`
`=sqrt((2xx(2.5//36pi))/((1/(4pixx9xx10^9))xx(3xx10^8)))`
`=4.08Vm^-1`
`B_0=(E_0)/c=4.08/(3xx10^8)=1.36xx10^-8T`
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