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The magnetic field in a plane electromag...

The magnetic field in a plane electromagnetic wave is given by
`B=(300muT) sin (5.0xx10^-5x^-1)(t-x//c)`
Find(i) the maximum electric field and (ii) The average energy density corresponding to the electric field.

Text Solution

Verified by Experts

Here, `B_0=300muT=3xx10^-4T`
(i) Maximum value of electric field, `E_0=cB_0`
`:. E_0=(3xx10^8)xx(2xx10^-4)`
`=9xx10^4Vm^-1`
(ii) Average energy density corresponding to
electric field
`u_E=1/4in_0E_0^2=1/4xx(8.85xx10^-12)xx(9xx10^4)^2`
`=19.91xx10^-4`
`=1.99xx10^-3Jm^-3`
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