Obtain the temperature ranges for ultraviolet part of radiation of EM waves. Use the formulae `lambda_m T=2.9xx10^-3mK`. Take frequency of ultraviolet part of radiations as `8xx10^14Hz` to `5xx10^17Hz`.

Explanation

The corresponding wavelength to the
frequency `8xx10^14Hz` is
`lambda_1=c/(v_1)=(3xx10^8)/(8xx10^14)=3.75xx10^-7m`
The corresponding wavelength to the frequency
`5xx10^17` is
`lambda_2=c/(v_2)=(3xx10^8)/(5xx10^17)=6xx10^-10m`
As `lambda_mT=2.9xx10^-3 or T=(2.9xx10^-3)/(lambda_m)`
For, `lambda_1=3.75xx10^-7m,`
`T_1=(2.9xx10^-3)/(3.75xx10^-7)=7.73xx10^3K`
For, `lambda_2=6xx10^-10m,`
`T_2=(2.9xx10^-3)/(6xx10^-10)=4.83xx10^6K`
Temperature range is `7.73xx10^3K to 4.83xx10^6K`