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Show that the average energy density of ...

Show that the average energy density of the electric field `vecE` equals the average energy density of the magnetic field `vecB`, in electromagnetic waves.

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To show that the average energy density of the electric field \( \vec{E} \) equals the average energy density of the magnetic field \( \vec{B} \) in electromagnetic waves, we can follow these steps: ### Step 1: Define the average energy density of the electric field The average energy density \( U_E \) of the electric field is given by the formula: \[ U_E = \frac{1}{2} \epsilon_0 E_{\text{rms}}^2 \] where \( \epsilon_0 \) is the permittivity of free space and \( E_{\text{rms}} \) is the root mean square value of the electric field. ...
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Show that the average energy density of the electric field vec E equals the average energy density of the magnetics fields vec B ?

Show that in an electromagnetic wave average energy density of the electric field vecE equals the average energy density of the magenetic field vecB .

Knowledge Check

  • Energy density of electric field E is

    A
    `1//2epsi_(0)E^(2)`
    B
    `epsi_(0)E^(2)`
    C
    `2epsi_(0)E^(2)`
    D
    `epsi_(0)E`
  • In an electromagnetic wave, the average energy density associated with magnetic field is:

    A
    `Li_(0)^(2)//2`
    B
    `B^(2)//2mu_(0)`
    C
    `mu_(0)B^(2)//2`
    D
    `mu_(0)//2B^(2)`
  • The electric and magnetic field of an electromagnetic wave is

    A
    in phase and parallel to each other
    B
    in opposite phase and perpenducular to each other
    C
    in opposite phase and parallel to each other
    D
    in phase and perpenducular to each other
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