Suppose that the electric field amplitude of an electromagnetic wave us `E_0=120 N// C` and that its frequency is `50.0 MHz`.
(a) Determine` B_0,omega,k` and `lambda`,
(b) find expressions for `E` and `B`.

Explanation

(a) `B_0=(E_0)/c =120/(3xx10^8)=4xx10^7T, omega =2piv=2xx3.14xx(50xx10^6)=3.14xx10^8rad//s`
`k=omega/c=(3.15xx10^8)/(3xx10^8)=1.05rad//m , lambda=c/v =(3xx10^8)/(50xx10^6)=6.00m`
(c) Expression for `vecE` is , `E=E_0 sin (kx-omegat)=(120N//C) sin [1.05rad//m)x-(3.14xx10^8rad//s)t] hatj`
Expression for `vecB` is, `B=B_0sin (kx-omegat)=(4xx10^-7T) sin [1.05rad//m)x-(3.14xx10^8rad//s)t] hatk`