The magnetic field of a beam emerging from a filter facing a floodlight is given by `B=12xx10^-8sin(1.20xx10^7z-3.60xx10^14t)T`.
What is the average intensity of the beam?

Explanation

To find the average intensity of the beam given the magnetic field \( B = 12 \times 10^{-8} \sin(1.20 \times 10^{7} z - 3.60 \times 10^{14} t) \, T \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Peak Magnetic Field**:
The given magnetic field can be expressed in the form \( B = B_0 \sin(kz - \omega t) \), where \( B_0 \) is the peak magnetic field. From the equation, we have:
\[
B_0 = 12 \times 10^{-8} \, T
...