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You are given a 2mu F parallel plate cap...

You are given a `2mu F` parallel plate capacitor. How would you establish an instantaneous displacement current fo 1mA in the space between its plates?

Text Solution

Verified by Experts

Here, `I_D=1mA =10^-3A, c=2mu F=2xx10^-6F, I_D=I=d/(dt) (CV)=C (dV)/(dt)`
Therefore, `(dV)/(dt) =(I_D)/C= (10^-3)/(2xx10^-6)=500V//s`
Therefore, applying a varying potential difference of `500V//s` would produce a displacement current of
desired value.
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