The magnetic field in a plane electromangnetic wave is given by
`B=(300muT) sin (5.0xx10^-5x^-1)(t-x//c)`
Find(i) the maximum electric field and (ii) The average energy density corresponding to the electric field.

Answer

`9xx10^4Vm^-1 ; 1.79xx10^-2Jm^-3`

Explanation

Here, `B_0=300muT=3000xx10^-6T`
`=3xx10^-4T`
`E_0=cB_0 =(3xx10^8)xx(3xx10^-4)`
`=9xx10^4Vm^-1`
`u_E=1/4in_0E_0^2=1/4xx(8.85xx10^-12)xx(9xx10^4)^2`
`=1.79xx10^-2Jm^-3`