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Dimension of (1)/(mu(0)epsilon(0)), wher...

Dimension of `(1)/(mu_(0)epsilon_(0))`, where symbols have usual meaning, are

A

`L^-1T`

B

`L^2T^2`

C

`L^2T^-2`

D

`LT^-1`

Text Solution

Verified by Experts

The correct Answer is:
c

As `c=1/(sqrt(in_0mu_0)), c^2=1/(mu_0in_0),`
so `[LT^-1]^2=1/(mu_0in_0) or [(mu_0in_0)]=L^2T^-2`
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