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A plane e.m. wave of wave intensity 6W//...

A plane e.m. wave of wave intensity `6W//m^2` strikes a small mirror of area `30cm^2`, held perpendicular to the approaching wave. The momentum transfered in `kgms^-1` by the wave to the mirror each second will be

A

`1.2xx10^(-10)`

B

`2.4xx10^-9`

C

`3.6xx10^-8`

D

`4.8xx10^-7`

Text Solution

Verified by Experts

The correct Answer is:
a
Momentum transferred in one second (i.e., force)
by em wave to the mirror is
`p=(2IA)/c=(2xx6xx(30xx10^-4))/(3xx10^8)`
`=1.2xx10^(-10) kgms^-1`
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